Rohit Sharma hit two successive sixes in the Super Over to help India claim the T20I series 3-0 against New Zealand in Hamilton
Hamilton: Rohit Sharma sealed India’s series win over New Zealand with a last-ball six in the Super Over in the third T20I in Hamilton on Wednesday (January 29).
In the five-T20I series, India hold an unassailable 3-0 lead. With 18 required to win in the Super Over, Rohit clinched the game with consecutive sixes off Tim Southee. India needed 10 off the final two balls.
Earlier, the actual match had ended in a tie with Mohammed Shami (2/32) defending nine runs in the final over. The hosts needed two off the final four balls but Shami was brilliant and gave just one run and took a wicket (Ross Taylor off the final ball). It was a superb comeback by Shami after being hit for a six by Taylor off the first ball in the final over.
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In the Super Over, Rohit hit 15 off four balls while his partner KL Rahul scored five from two deliveries. India scored 20 in the Super Over.
He is on a roll today as brings up his 20th T20I FIFTY off 23 deliveries.
His first half-century of the series so far 💪💪 pic.twitter.com/NGuY3qQCu1
Earlier, Rohit hit a 40-ball 65 (6x4, 3x6) as India scored 179/5 in 20 overs. He and Rahul (27) put on 89 runs in nine overs for the first wicket. Despite a blazing start, the “Men in Blue” could not cross the 200-run mark as wickets tumbled. Captain Virat Kohli made 38.
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In reply, New Zealand were in control, thanks to skipper Kane Williamson’s blistering 48-ball 95 (8x4, 6x6). But his dismissal in the final over, brought India back. Ross Taylor was bowled off the final ball as the match ended in a tie.
WHAT A MATCH! 🔥🔥 win in super over, take an unassailable lead of 3️⃣ - 0️⃣ in the 5-match series. 🇮🇳 pic.twitter.com/4Lc1AdFZZg
— BCCI (@BCCI)Jasprit Bumrah had an off day as he went for 45 runs in four overs without a wicket. Later, he gave away 17 runs in the Super Over.
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